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5x^2-25x+4=-24
We move all terms to the left:
5x^2-25x+4-(-24)=0
We add all the numbers together, and all the variables
5x^2-25x+28=0
a = 5; b = -25; c = +28;
Δ = b2-4ac
Δ = -252-4·5·28
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{65}}{2*5}=\frac{25-\sqrt{65}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{65}}{2*5}=\frac{25+\sqrt{65}}{10} $
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